An Ideal Transformer Example: Difference between revisions

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Therefore, <math>{e_{1}}(t) = {V_{1}}\cos(120 \pi t)</math>
Therefore, <math>{e_{1}}(t) = {V_{1}}\cos(120 \pi t)</math>
Now <math>{Z_{th}}</math> is the impedance seen by the voltage source supplying winding 1.

Revision as of 17:31, 15 January 2010

Consider a simple, transformer with two windings. Find the current provided by the voltage source.

  • Winding 1 has a sinusoidal voltage of 12020° applied to it at a frequency of 60Hz.
  • N1N2=3
  • The combined load on winding 2 is ZL=(5+j3)Ω

Solution

e1(t)=V1cos(ωt)

ω=2πf, so ω=120π

Therefore, e1(t)=V1cos(120πt)

Now Zth is the impedance seen by the voltage source supplying winding 1.