Problem Set 1: Difference between revisions

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<math>S=P+iQ\!</math>
<math>S=P+iQ\!</math>


Apparent power in the imaginary and real coordinate system is the hypotenuse of real and reactive power and are related using the equation of a circle.
Apparent power in the imaginary and real coordinate system is the hypotenuse of real and reactive power and can be expressed using the equation of a circle.


<math>S^{2}=P^{2}+Q^{2}\!</math>
<math>S^{2}=P^{2}+Q^{2}\!</math>

Revision as of 23:36, 8 February 2010

Problem


Find the core inductance and resistance of a transformer using measurements Voc=5V, Ioc=3A, and Poc =10W.


Solution

Power is stored in resistors because of their linear behavior.

Poc=Voc2/R

Both Poc and Voc are giving so solve for R

R=Voc2/Poc=5V/10W=2.5Ohms Answer

Apparent power relation to voltage and current is

S2=|Voc*Ioc*|2

The magnitude for current and voltage are given in the problem statement. Subtitute in known values and solve.

S2=(5V*3A)2=225(VA)2

Apparent power S is complex. It has a real part P, real power, and an imaginary part Q, reactive power.

S=P+iQ

Apparent power in the imaginary and real coordinate system is the hypotenuse of real and reactive power and can be expressed using the equation of a circle.

S2=P2+Q2

Use the apparent power and the real power to find the reactive power

Q=S2P2=2252102=224.8VAr Answer

Reactive power is stored in non-linear impedance represented as X. In this case X is inductance.

Q=Voc2/X

X=Voc2/Q=5V2/224.8VAr=0.11H