State Space Form: Difference between revisions
Jump to navigation
Jump to search
No edit summary |
No edit summary |
||
Line 1: | Line 1: | ||
⚫ | |||
== State Space Form == |
|||
Consider the differential equation |
|||
<math>\frac{d^2 y}{d t^2}+2\frac{xy}{dt}+3y=f(t)</math> <br> |
|||
or <br> |
|||
<math>\ddot y +2\dot y + 3y =f(t) </math> <br> |
|||
The state of this equation can be described using what is called state space form. State space form gives the blah blah more here. |
|||
let <math>x1 = y</math> <br> |
|||
let <math>x2=\dot y </math> <br> |
|||
so <math>\dot x2 = \ddot y </math> <br> |
|||
⚫ | |||
We can now re-write the equation above to be:<br> |
|||
<math>\dot x2 + 2x2 + 3 x1 = f(t)</math><br> |
|||
so <br><math>\dot x2 = -3x1 -2x2 + f(t)</math><br> |
|||
and from the definition above <br><math>\dot x1 = x2</math><br> |
|||
We can take this and put it into matrix form: |
|||
<math> |
|||
\begin{bmatrix} |
|||
\dot x1 \\ |
|||
\dot x2 \\ |
|||
\end{bmatrix} |
|||
= |
|||
\begin{bmatrix} |
|||
0 & 1 \\ |
|||
-3 & -2 \\ |
|||
\end{bmatrix} |
|||
\begin{bmatrix} |
|||
x1 \\ |
|||
x2 \\ |
|||
\end{bmatrix} |
|||
+ |
|||
\begin{bmatrix} |
|||
0 \\ |
|||
1 \\ |
|||
\end{bmatrix} |
|||
f(t) |
|||
</math><br> |
|||
Or, more generally,<br> |
|||
<math>\mathbf{\dot x} = \mathbf{Ax+B}f</math><br> |
|||
This is called the state space representation of the differential equation. |
Revision as of 11:08, 30 August 2010
In my Signals and Systems II class at University of Idaho, we are learning about the state space form of representing a solution to a LTI differential equation. I'll add more here soon.
Consider the differential equation
or
The state of this equation can be described using what is called state space form. State space form gives the blah blah more here.
let
let
so
We can now re-write the equation above to be:
so
and from the definition above
We can take this and put it into matrix form:
Or, more generally,
This is called the state space representation of the differential equation.