Fourier transform: Difference between revisions
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Suppose that we have some function, say <math> \beta (t) </math>, that is nonperiodic and finite in duration.<br> |
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This means that <math> \beta(t)=0 </math> for some <math> T_\alpha < \left | t \right | </math> |
Revision as of 08:29, 8 December 2004
An initially identity that is useful:
Suppose that we have some function, say , that is nonperiodic and finite in duration.
This means that for some