Signals and systems/GF Fourier: Difference between revisions

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*Multiply by the complex conjugate
*Multiply by the complex conjugate


<math> \int_{-T/2}^{T/2} x(t) e^{{-j2\pi mt}/T} dt = \sum_{n=-\infty}^\infty \alpha_n \frac{Te^{{j2\pi (n-m)t}/T}}{{j2\pi (n-m)}} \bigg|_{-T/2}^{T/2} = \sum_{n=-\infty}^\infty \alpha_n T\delta_{n,m}</math>  
<math> \int_{-T/2}^{T/2} x(t) e^{{-j2\pi mt}/T} dt = \sum_{n=-\infty}^\infty \alpha_n \frac{Te^{{j2\pi (n-m)t}/T}}{{j2\pi (n-m)}} \bigg|_{-T/2}^{T/2} = \sum_{n=-\infty}^\infty \alpha_n T\delta_{n,m} = T\alpha_m</math>  


*<math> \frac{Te^{{j2\pi (n-m)t}/T}}{{j2\pi (n-m)}} \bigg|_{-T/2}^{T/2} = T\frac{e^{j\pi(n-m)}-e^{-j\pi(n-m)}}{j2\pi(n-m)} = T \frac{\sin\pi(n-m)}{\pi(n-m)} =  \begin{Bmatrix} T, n=m \\ 0, n\ne m \end{Bmatrix} = \sum_{n=-\infty}^\infty \alpha_n T\delta_{n,m}</math>  
*<math> \frac{Te^{{j2\pi (n-m)t}/T}}{{j2\pi (n-m)}} \bigg|_{-T/2}^{T/2} = T\frac{e^{j\pi(n-m)}-e^{-j\pi(n-m)}}{j2\pi(n-m)} = T \frac{\sin\pi(n-m)}{\pi(n-m)} =  \begin{Bmatrix} T, n=m \\ 0, n\ne m \end{Bmatrix} = T\delta_{n,m}</math>  


** Using L'Hopitals to evaluate the <math>\frac{T\cdot 0}{0}</math> case. Note that n & m are integers
** Using L'Hopitals to evaluate the <math>\frac{T\cdot 0}{0}</math> case. Note that n & m are integers
<math> \alpha_m = \frac{1}{T}\int_{-T/2}^{T/2} x(t) e^{{-j2\pi mt}/T} dt


== <math> \left \langle Bra \mid Ket \right \rangle </math> Notation ==
== <math> \left \langle Bra \mid Ket \right \rangle </math> Notation ==

Revision as of 22:23, 29 October 2006

Fourier series

The Fourier series is used to analyze arbitrary periodic functions by showing them as a composite of sines and cosines.

A function is considered periodic if x(t)=x(t+T) for T≠0.

The exponential form of the Fourier series is defined as x(t)=∑n=−∞∞αnej2πnt/T

Determining the coefficient αn

x(t)=∑n=−∞∞αnej2πnt/T

  • The definition of the Fourier series

∫−T/2T/2x(t)dt=∑n=−∞∞αn∫−T/2T/2ej2πnt/Tdt

  • Integrating both sides for one period. The range of integration is arbitrary, but using ∫−T/2T/2 scales nicely when extending the Fourier series to a non-periodic function

∫−T/2T/2x(t)e−j2πmt/Tdt=∑n=−∞∞αn∫−T/2T/2ej2πnt/Te−j2πmt/Tdt=∑n=−∞∞αn∫−T/2T/2ej2π(n−m)t/Tdt

  • Multiply by the complex conjugate

∫−T/2T/2x(t)e−j2πmt/Tdt=∑n=−∞∞αnTej2π(n−m)t/Tj2π(n−m)|−T/2T/2=∑n=−∞∞αnTδn,m=Tαm

  • Tej2π(n−m)t/Tj2π(n−m)|−T/2T/2=Tejπ(n−m)−e−jπ(n−m)j2π(n−m)=Tsin⁡π(n−m)π(n−m)={T,n=m0,n≠m}=Tδn,m
    • Using L'Hopitals to evaluate the T⋅00 case. Note that n & m are integers

αm=1T∫−T/2T/2x(t)e−j2πmt/Tdt==<math>⟨Bra∣Ket⟩ Notation ==

Linear Time Invariant Systems

Changing Basis Functions

Identities

ejθ=cos⁡θ+jsin⁡θ

sin⁡x=ejx−e−jx2j

cos⁡x=ejx+e−jx2

⟨n∣m⟩=Tδn,m