10/01 - Vectors & Functions: Difference between revisions

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==Changing from one orthogonal Basis Functions to another==
==Changing from one orthogonal Basis Functions to another==
If you have a vector <math> \hat v = \sum_{j=1}^3 a_j \hat a_j </math> and wish to change it to <math> \hat v = \sum_{j=1}^3 b_j \hat b_j</math>
If you have a vector <math> \hat v = \sum_{j=1}^3 a_j \hat a_j </math> and wish to change it to <math> \hat v = \sum_{j=1}^3 b_j \hat b_j</math>
:<math> \hat v = \sum_{j=1}^3 a_j \hat a_j </math>
:<math> \hat v = \sum_{j=1}^3 a_j \hat a_j = \hat v \cdot \hat b_m= \sum_{j=1}^3 a_j \hat a_j \cdot \hat b_m = \sum_{j=1}^3 a_j \underbrace{(\hat a_j \cdot \hat b_m )}_{proj of \hat a_j on \hat b_m} = \sum_{j=1}^3 a_j k_m \delta mj = \sum_{j=1}^3 a_m k_m</math>
:<math> \hat v \cdot \hat b_m= \sum_{j=1}^3 a_j \hat a_j \cdot \hat b_m = \sum_{j=1}^3 a_j \underbrace{(\hat a_j \cdot \hat b_m )}_{proj of \hat a_j on \hat b_m} = \sum_{j=1}^3 a_j k_m \delta mj = \sum_{j=1}^3 a_m k_m</math>

Revision as of 15:59, 9 November 2008

Vectors & Functions

  • How to related the vector v to the sampling?

We could sample a continuous function every T seconds, creating a "bar graph".

f(t)=∑i=0N−1f(iT)⏟coefficients⋅p(t−iT)⏟basisfunctions

  • Where p(t) is a rectangle 1 unit high and T units wide

In an effort to make this more exact, will will continue to shrink the rectangle down to the Dirac Delta function, δ

  • δ(x)={+∞,x=00,x≠0
  • ∫−∞∞δ(x)dx=1.

By using the Dirac Delta function the summation becomes an integral

f(t)=∫−∞∞f(u)⋅δ(t−u)du

Changing from one orthogonal Basis Functions to another

If you have a vector v^=∑j=13aja^j and wish to change it to v^=∑j=13bjb^j

v^=∑j=13aja^j=v^⋅b^m=∑j=13aja^j⋅b^m=∑j=13aj(a^j⋅b^m)⏟projofa^jonb^m=∑j=13ajkmδmj=∑j=13amkm