10/3,6 - The Game: Difference between revisions

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==Example==
==Example==
Let <math>x(t) = e^{j2\pi nt/T}</math>
Let <math>x(t) = e^{j2\pi nt/T} = e^{j2\pi \omega_n t}</math>
 
<math>\int_{-\infty}^{\infty} e^{j2\pi \omega_n t} h(t-\lambda)\, dx</math>

Revision as of 19:24, 11 November 2008

The Game

The idea behind the game is to use linearity (superposition and proportionality) and time invariance to find an output for a given input. An initial input and output are given.

Input LTI System Output Reason
δ(t) ⟹ h(t) Given
δ(t−λ) ⟹ h(t−λ) Time Invarience
x(λ)δ(t−λ) ⟹ x(λ)h(t−λ) Proportionality
x(t)=∫−∞∞x(λ)δ(t−λ)dx ⟹ ∫−∞∞x(λ)h(t−λ)dx⏟ConvolutionIntegral Superposition

With the derived equation, note that you can put in any x(t) to find the given output. Just change your t for a lambda and plug n chug.

Example

Let x(t)=ej2πnt/T=ej2πωnt

∫−∞∞ej2πωnth(t−λ)dx