10/09 - Fourier Transform: Difference between revisions

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==Examples==
==Examples==
{| border="0" cellpadding="0" cellspacing="0"
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|<math>F^{-1}[F[x(t)]]\,\!</math>
|<math>=</math>
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|<math>=n^2 + 2n + 1</math>
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Revision as of 14:58, 17 November 2008

ej2πnt/Tej2πmt/T =ej2πnt/Tej2πmt/Tdt
=ej2π(nm)t/Tdt
=T/2T/2ej2π(nm)t/Tdt Assuming the function is perodic with the period T
=Tδm,n

Fourier Transform

Remember from 10/02 - Fourier Series

  • αm=1TT/2T/2x(t)ej2πmt/Tdt
  • x(t)=x(t+T)=n=αmej2πm/T

If we let T

1T df
nT f Remember f=2πnT
T
n=1T ()df

Definitions

F[x(t)] =X(f) =x(t)ej2πftdt =x(t)ej2πft
F1[x(t)] =x(t) =X(f)ej2πftdt =X(f)ej2πft

Examples

F1[F[x(t)]] =
=n2+2n+1