Fourier Transform Properties: Difference between revisions

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New page: ====Max Woesner==== Find <math>\mathcal{F}[cos(w_0t)g(t)]\!</math><br> Recall <math> w_0 = 2\pi f_0\!</math>, so <math>\mathcal{F}[cos(w_0t)g(t)] = \mathcal{F}[cos(2\pi f_0t)g(t)] = \int_{...
 
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====Max Woesner====
[[Max Woesner|<b>Max Woesner</b>]]<br>
Find <math>\mathcal{F}[cos(w_0t)g(t)]\!</math><br>
Find <math>\mathcal{F}[cos(w_0t)g(t)]\!</math><br>
Recall <math> w_0 = 2\pi f_0\!</math>, so <math>\mathcal{F}[cos(w_0t)g(t)] = \mathcal{F}[cos(2\pi f_0t)g(t)] = \int_{-\infty}^{\infty}cos(2\pi f_0t)g(t)e^{-j2\pi ft}dt\!</math><br>
Recall <math> w_0 = 2\pi f_0\!</math>, so <math>\mathcal{F}[cos(w_0t)g(t)] = \mathcal{F}[cos(2\pi f_0t)g(t)] = \int_{-\infty}^{\infty}cos(2\pi f_0t)g(t)e^{-j2\pi ft}dt\!</math><br>

Revision as of 18:14, 15 October 2009

Max Woesner
Find [cos(w0t)g(t)]
Recall w0=2πf0, so [cos(w0t)g(t)]=[cos(2πf0t)g(t)]=cos(2πf0t)g(t)ej2πftdt
Also recall cos(θ)=12(ejθ+ejθ),so cos(2πf0t)g(t)ej2πftdt=12[ej2πf0t+ej2πf0t]g(t)ej2πftdt
Now 12[ej2πf0t+ej2πf0t]g(t)ej2πftdt=12ej2π(ff0)tg(t)dt+12ej2π(f+f0)tg(t)dt=12G(ff0)+12G(f+f0)
So [cos(w0t)g(t)]=12[G(ff0)+G(f+f0)]