Fourier Transform Properties: Difference between revisions

From Class Wiki
Jump to navigation Jump to search
No edit summary
No edit summary
Line 1: Line 1:
[[Max Woesner|<b>Max Woesner</b>]]<br>
[[Max Woesner|<b><u>Max Woesner</u></b>]]<br><br>
Find <math>\mathcal{F}[cos(w_0t)g(t)]\!</math><br>
Find <math>\mathcal{F}[cos(w_0t)g(t)]\!</math><br>
Recall <math> w_0 = 2\pi f_0\!</math>, so <math>\mathcal{F}[cos(w_0t)g(t)] = \mathcal{F}[cos(2\pi f_0t)g(t)] = \int_{-\infty}^{\infty}cos(2\pi f_0t)g(t)e^{-j2\pi ft}dt\!</math><br>
Recall <math> w_0 = 2\pi f_0\!</math>, so <math>\mathcal{F}[cos(w_0t)g(t)] = \mathcal{F}[cos(2\pi f_0t)g(t)] = \int_{-\infty}^{\infty}cos(2\pi f_0t)g(t)e^{-j2\pi ft}dt\!</math><br>

Revision as of 18:25, 15 October 2009

Max Woesner

Find ℱ[cos(w0t)g(t)]
Recall w0=2πf0, so ℱ[cos(w0t)g(t)]=ℱ[cos(2πf0t)g(t)]=∫−∞∞cos(2πf0t)g(t)e−j2πftdt
Also recall cos(θ)=12(ejθ+e−jθ),so ∫−∞∞cos(2πf0t)g(t)e−j2πftdt=∫−∞∞12[ej2πf0t+e−j2πf0t]g(t)e−j2πftdt
Now ∫−∞∞12[ej2πf0t+e−j2πf0t]g(t)e−j2πftdt=12∫−∞∞e−j2π(f−f0)tg(t)dt+12∫−∞∞e−j2π(f+f0)tg(t)dt=12G(f−f0)+12G(f+f0)
So ℱ[cos(w0t)g(t)]=12[G(f−f0)+G(f+f0)]