User talk:Gregory.peterson: Difference between revisions
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<math>m\ddot{x}+b\dot{x}-k(f-x)=0</math> | |||
<math>\ddot{x}+\frac{b}{m}\dot{x}+\frac{k}{m}x=\frac{k}{m}f</math> |
Revision as of 14:55, 22 October 2009