Coupled Oscillator: Jonathan Schreven: Difference between revisions
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Using F=ma we can then find our equations of equilibrium. | Using F=ma we can then find our equations of equilibrium. | ||
:'''Equation 1''' | |||
:<math>\begin{alignat}{3} | :<math>\begin{alignat}{3} | ||
F & = ma \\ | F & = ma \\ | ||
Line 16: | Line 16: | ||
-{k_1+k_2 \over {m_1}}x_1+{k_2 \over {m_1}}x_2 & = \ddot{x_1} \\ | -{k_1+k_2 \over {m_1}}x_1+{k_2 \over {m_1}}x_2 & = \ddot{x_1} \\ | ||
\end{alignat}</math> | \end{alignat}</math> | ||
:'''Equation 2''' | |||
:<math>\begin{alignat}{3} | |||
F & = ma \\ | |||
F & = m\ddot{x} \\ | |||
-k_2(x_2-x_1) & = m_2\ddot{x_2} \\ | |||
{-k_2(x_2-x_1) \over {m_2}} & = \ddot{x_2} \\ | |||
-{k_2 \over {m_2}}x_2+{k_2 \over {m_2}}x_1 & = \ddot{x_2} \\ | |||
\end{alignat}</math> | |||
:'''Equation 3''' | |||
:<math>\dot{x_1}=\dot{x_1}</math> | |||
:'''Equation 4''' | |||
:<math>\dot{x_2}=\dot{x_2}</math> |
Revision as of 18:41, 9 December 2009
Coupled Oscillator System
In this problem I would like to explore the solution of a double spring/mass system under the assumption that the blocks are resting on a smooth surface. Our system might look something like this.
Using F=ma we can then find our equations of equilibrium.
- Equation 1
- Equation 2
- Equation 3
- Equation 4