Example problems of magnetic circuits: Difference between revisions

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Solution:
Solution:
First we need to find the permeability of copper <math> \mu </math> given by the equation <br> <math> \mu = \mu_0 (1 + \chi_m)</math> <br> <br>
First we need to find the permeability of copper <math> \mu </math> given by the equation <br> <math> \mu = \mu_0 (1 + \chi_m)</math> <br> <br>
Which yeilds <math> \mu = 4 &times \pi &times 10^{-7}(1+-9.7 &times 10^{-6}) = 1.2566 &times 10^{-6} </math> <br><br>
Which yeilds <math> \mu = 4 \times \pi \times 10^{-7}(1+-9.7 \times 10^{-6}) = 1.2566 \times 10^{-6} </math> <br><br>
Now with this, the length and cross sectional area of the core we can solve for reluctance <math> R_c </math> by: <br>
Now with this, the length and cross sectional area of the core we can solve for reluctance <math> R_c </math> by: <br>



Revision as of 17:51, 10 January 2010

Given:

A copper core with susceptibility Failed to parse (syntax error): {\displaystyle \chi_m = -9.7 &times 10^{-6} }

length of core L = 1 m

Gap length g = .01 m

cross sectional area A = .1 m

current I = 10A

N = 5 turns


Find: B

Solution: First we need to find the permeability of copper given by the equation


Which yeilds

Now with this, the length and cross sectional area of the core we can solve for reluctance by:

<math> R_c = \frac{L}{\mu A} = \frac{1}{1.2566x10^{-6}*.1} = 7.96x10^{6}