Laplace Transform: Difference between revisions

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New page: :<math>F(s) = \mathcal{L} \left\{1\right\}=\int_0^{\infty} e^{-st} \,dt = </math> <math> \frac {1}{s}</math> Normal 0 false false false EN-US X-NONE X-NO...
 
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:<math>F(s) = \mathcal{L} \left\{1\right\}=\int_0^{\infty} e^{-st} \,dt = </math> <math> \frac {1}{s}</math>
:<math>F(s) = \mathcal{L} \left\{1\right\}=\int_0^{\infty} e^{-st} \,dt = </math> <math> \frac {1}{s}</math>


    Normal  0              false  false  false      EN-US  X-NONE  X-NONE                                                    MicrosoftInternetExplorer4
:<math>F(s) = \mathcal{L} \left\{t^2\right\}=\int_0^{\infty} e^{-st} t^2 \,dt = </math> <math> \frac {n!}{s^{n+1}}</math>
 
:<math>F(s) = \mathcal{L} \left\{t^2\right\}=\int_0^{\infty} e^{-st} \,dt = </math> <math> \frac {1}{s}</math>

Revision as of 18:27, 11 January 2010

F(s)={1}=0estdt= 1s
F(s)={t2}=0estt2dt= n!sn+1