Integrator Amplifier: Difference between revisions

From Class Wiki
Jump to navigation Jump to search
No edit summary
(fixed sources likes and cited material)
Line 9: Line 9:
</math>
</math>


"<math>R_{2}</math> ; Provides negative feedback for low output impedance needs. But it also distorts the output."<sup>1</sup>
"<math>R_{2}</math> ; Provides negative feedback for low output impedance needs. But it also distorts the output."<ref><sup>Quick Study "Electronics 1, Part 2"</sup></ref>


The use of an integrator circuit is the opposite of a differentiator circuit. In other words, If you have a triangle wave input and you differentiate it you will get a square wave output. If you run the square wave as the input to an integrator circuit you will end up with the triangle wave for the output<sup>2</sup>.
The use of an integrator circuit is the opposite of a differentiator circuit. In other words, If you have a triangle wave input and you differentiate it you will get a square wave output. If you run the square wave as the input to an integrator circuit you will end up with the triangle wave for the output<ref><sup>Scherz, P: ''Practical Electronics for Inventors 2nd ed'', page 545. </sup></ref>.
The resistor (<math>R_{2}</math>) is used to provide feedback<sup>3</sup> of the output DC voltage. Without this, circuit wouldn't perform as calculated because of the un-ideal conditions of real life.
The resistor (<math>R_{2}</math>) is used to provide feedback<ref><sup>[[Feedback_in_Amplifiers]]</sup></ref> of the output DC voltage. Without this, circuit wouldn't perform as calculated because of the un-ideal conditions of real life.


==Contributers==
==Contributers==
Line 30: Line 30:


==Sources==
==Sources==
<references/>

<sup>1</sup> Quick Study "Electronics 1, Part 2"

<sup>2</sup> Practical Electronics for Inventors (p545, 2nd edition)

<sup>3</sup> [[Feedback_in_Amplifiers]]

Revision as of 19:19, 17 January 2010

Amplifiers

Integrator

Graph of a typical Integrator Amp circuit (drawing redrawn by Ben Henry)

The circuit at right integrates the input voltage by using an amplifier.

" ; Provides negative feedback for low output impedance needs. But it also distorts the output."<ref>Quick Study "Electronics 1, Part 2"</ref>

The use of an integrator circuit is the opposite of a differentiator circuit. In other words, If you have a triangle wave input and you differentiate it you will get a square wave output. If you run the square wave as the input to an integrator circuit you will end up with the triangle wave for the output<ref>Scherz, P: Practical Electronics for Inventors 2nd ed, page 545. </ref>. The resistor () is used to provide feedback<ref>Feedback_in_Amplifiers</ref> of the output DC voltage. Without this, circuit wouldn't perform as calculated because of the un-ideal conditions of real life.

Contributers

--Benjamin.henry 23:15, 10 January 2010 (UTC)

Reviewers

Greg Fong

Victor Shepherd

  • I agree with Greg just like you did with square sine wave do the same with triangle wave instead of ^^^, makes it confusing and I don't believe that's a standard way of representing it.
  • I will add one more thing. You don't need to have the types of waves within "".

Sources

<references/>