EMEC: Difference between revisions

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<math>H_m=(\frac{Ni}{l_m})</math>
<math>H_m=(\frac{Ni}{l_m})</math>


<math>H_m=(\frac{20 x 2.5}{.141}= 354.6\ A /m)</math>
<math>H_m=\frac{20 x 2.5}{.141}= 354.6\ A /m)</math>

Revision as of 19:51, 18 January 2010

rm=(12)OD+ID2

Hm=(Nilm)

Hm=20x2.5.141=354.6A/m)