Chapter 5: Difference between revisions

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| Cutoff|| <math>v_{GS}<V_{to}\,</math> || 0
| Cutoff|| <math>v_{GS}<V_{to}\,</math> || 0
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|-
| Triode|| <math>v_{DS} \le v_{GS}- V_{to}\,</math> and <math> v_{GS} \ge V_{to}</math> || <math>i_D \propto v_{DS}</math>
| Triode|| <math>v_{DS} \le v_{GS}- V_{to}\,</math> and <math> v_{GS} \ge V_{to}</math> || <math>i_D = K [2(v_{GS}-V_{to})v_{DS}-v^2_{DS}]</math>
|-
|-
| Saturation || <math>v_{DS} \ge v_{GS}- V_{to}\,</math> ||  
| Saturation || <math>v_{DS} \ge v_{GS}- V_{to}\,</math> ||  

Revision as of 23:02, 14 March 2010

NMOS Transistor

  • N-channel enhancement-mode MOSFET (metal-oxide semiconductor field effect transistor)
Nmos regions
Region Conditions iD
Cutoff vGS<Vto 0
Triode vDSvGSVto and vGSVto iD=K[2(vGSVto)vDSvDS2]
Saturation vDSvGSVto
  • The threshold voltage, Vto, is the minimum VGS needed to move the transistor from the Cutoff to Triode region. When is reached, a channel forms beneath the gate, allowing current to flow.
  • Vto is usually on the order of a couple of volts
  • For small values of VDS, iD is proportional to VDS. The device behaves as a resistor whose value depends on vGS
  • "Now consider what happens if we continue to increase VDS. Because of the current flow, the voltages between points along the channel and the source become greater as we move toward the drain. Thus, the voltage between gate and channel becomes smaller as we move toward the rain, resulting in a tapering of the channel thickness as illustrated in Figure 5.5. Because of the tapering of the channel, its resistance becomes larger with increasing vDS, resuling in a lower rate of increase of iD." <ref>Electronics p. 291</ref>

References

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