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<math> B = \dfrac{-R}{R^2+w^2L^2} \,\!</math> |
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<math> B = \dfrac{-R}{R^2+w^2L^2} \,\!</math> |
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<math> I(s)= \dfrac{a+jb}{s+jw} + \dfrac{a-jb}{s-jw} + \dfrac{B}{s+R/L} \,\!</math> |
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<math> I(s)= \dfrac{(a+jb)(s-jw)+(a-jb)(s+jw)}{s^2+w^2}+\dfrac{B}{s^2+w^2} \,\!</math> |
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<math> I(s)= \dfrac{2as}{s^2+w^2} + \dfrac{2bw}{s^2+w^2} + \dfrac{B}{s+R/L} \,\!</math> |
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<math> a = \dfrac{1/2R}{R^2+w^2L^2} \,\!</math> |
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<math> b = \dfrac{1/2wL}{R^2+w^2L^2} \,\!</math> |
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<math> i(t) = \mathcal{L}^{-1} \{I(s)\} \,\!</math> |
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<math> i(t) = 2a \cos wt + 2b\sin wt + BE^{-Rt/L} -ie^{-Rt/L} \,\!</math> |
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<math> i(t) = 2 \dfrac{R}{R^2+w^2L^2} \cos wt + 2 \dfrac{wL}{R^2+w^2L^2} \sin wt + \dfrac{-R}{R^2+w^2L^2} e^{-Rt/L} -ie^{-Rt/L} \,\!</math> |
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This Solves the Series RL circuit for the current throughout the circuit, given initial conditions or no initial conditions |
I decided that I would attempt to perform a simple analysis of a series RL circuit, which could then be used to do a more complex analysis on a basic transformer. I have always had interest in electronics, and transformers are key to basic electronics.
I decided that i would do the analysis of a RL circuit with the variables instead of given values.
Given:
V(t)=
V(s)=
I(0)=i
The Laplace transform for an inductor:
=
The Laplace transform for a resistor:
=
Therefore the Resulting Equation for the system after applying the Laplace Transform:
A series of algebraic manipulations follows to come up with I(s):
We can then use partial fraction manipulation to expand the expression:
After a lot of messy math and work:
This Solves the Series RL circuit for the current throughout the circuit, given initial conditions or no initial conditions