Code Examples from Class
Jump to navigation
Jump to search
- Factorial
; Factorial Calculation ; The answer is in R10 ; Rob Frohne 2013 GLOBAL Reset_Handler AREA Factorial, CODE, READONLY ENTRY Reset_Handler movs r8, #0 ; Take the factorial of this number, n. mov r10, #1 ; 0! and 1! are 1 beq stop ; If r8 is zero we are done cmp r8, #1 ; If r8 is 1, beq stop ; we are done subs r9, r8, #1 ; n-1 loop mulne r10, r9, r8 ; n(n-1) mov r8, r10 subs r9, r9, #1 bne loop stop b stop END
- 64 Bit Add
VAL1A EQU 0xffffffff VAL1B EQU 0x0000000f VAL2A EQU 0x00000001 VAL2B EQU 0x00000001 AREA LongAdd, CODE ENTRY ldr R0, = VAL1A ldr R1, = VAL1B ldr R2, = VAL2A ldr R3, = VAL2B adds R8,R0,R1 adcs R9,R1,R3 stop b stop END
- Copy to RAM
AREA Exaddress, CODE, READONLY EXPORT Reset_Handler Reset_Handler LDR R9, =list mov R7, #4 ; number in list ldr r6, =datastart loop ldr r8,[r9],#4 str r8,[r6],#4 subs r7,r7,#1 bne loop stop b stop ALIGN list DCW 0x1111, 0x2222, 0x3333, 0x4444, 0x5555 ALIGN string DCB "This is a test.",0 string2 DCB 'T','h','i' ALIGN AREA Thedata, DATA, NOINIT, READWRITE datastart SPACE 20 END
- Subroutine Example1
; First Subroutine Example ; This program demonstrates using a subroutine, ; saving registers on the stack, etc. ; Rob Frohne, 1/3/2013 stack_start EQU 0x40001000 AREA Subroutine_Example, CODE ENTRY Start ldr sp, =stack_start ; Tell where we will place the stack. ; (It goes down (lower addresses from here.) mov r1, #1 ; Store some numebers in some registers mov r2, #2 mov r3, #3 bl subroutine stop b stop ; This subroutine saves the registers, ; messes up the registers locally, ; then restores the registers and returns. subroutine stmfd sp!, {r1-r2,lr} ; save used registers and the link register (r14) mov r1,#0xffffffff ; mess up the registers mov r2, r1 ldmfd sp!, {r1,r2,pc} ; pop the stack and return END
- Minimum of a Signed Number
; This program finds the minimum of a list of constant words in signed format ; The result is in r3 at the end of the routine. ; Rob Frohne 10/30/2013 AREA Program, CODE, READONLY ENTRY ldr r0,=end ; load the beginning address of the code & initialize it as the pointer. ldr r2,=begin ; load the ending address of the code. mov r3,#0x7fffffff ; Initialize r3 as the most positive number. loop ldr r6,[r2],#4 ; load the next data into r6 and post increment r2 for the next data. cmp r6,r3 ; Find out if r6 > r3. result from r6-r3 like subs r7,r6,r3 without r6 necessary. bgt no_update ; If it is no update. mov r3,r6 ; update if r6 is lower than r3. no_update cmp r0,r2 ; are we at the end yet bne loop ; if r7 != 0 then keep looping stop b stop ALIGN begin DCD 0x8fffffff, 0x55555555, 0x44444444, 0x77777777, 0xffffffff end END
- Compare Two Null Terminated Strings
; Subroutine to compare two null terminated ASCII strings. ; The address where the two strings start are in r0 and r1 ; The return is in r0, 1 for match and 0 for don't match. ; If they don't match, r1 gives the number of the first ; character that didn't match, starting with 0. ; r2 and r3 are not protected. ; Rob Frohne 11/6/2013 stack_start EQU 0x40001000 AREA String_Compare, CODE ENTRY Start ldr sp, =stack_start ; Tell where we will place the stack. ; (It goes down (lower addresses from here.) ldr r0, =string1 ldr r1, =string2 bl compare_strings stop b stop compare_strings stmfd sp!, {r4,r5,lr} ; save used registers and the link register (r14) mov r2, #0 ; Initialize the counter for the first position. loop ldrb r4,[r0],#1 ldrb r5,[r1],#1 cmp r5,r4 bne do_not_match cmp r4, #0 ; check for end of string. beq match add r2, #1 b loop do_not_match mov r0, #0 ; don't match b finish match mov r0, #1 finish ldmfd sp!, {r4,r5,pc} ; pop the stack and return string1 DCB "This is the first string.",00 ; For testing purposes. ALIGN string2 DCB "This is the second string.",00 ALIGN END