Example problems of magnetic circuits

Given:

A copper core with susceptibility ${\chi }_m=-9.7x10^{-6}$

length of core L = 1 m

Gap length g = .01 m

cross sectional area A = .1 m

current I = 10A

N = 5 turns

Find: B

Solution: First we need to find the permeability of copper $\mu$ given by the equation
$\mu ={\mu }_0(1+{\chi }_m)$

Which yeilds $\mu =4*\pi *10^{-7}(1+-9.7x10^{-6})=1.2566x10^{-6}$

Now with this, the length and cross sectional area of the core we can solve for reluctance $R_c$ by:

<math> R_c = \frac{L}{\mu A} = \frac{1}{1.2566x10^{-6}*.1} = 7.96x10^{6}