Fourier Transform Properties

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Max Woesner

Find ℱ[cos(w0t)g(t)]
Recall w0=2πf0, so ℱ[cos(w0t)g(t)]=ℱ[cos(2πf0t)g(t)]=∫−∞∞cos(2πf0t)g(t)e−j2πftdt
Also recall cos(θ)=12(ejθ+e−jθ),so ∫−∞∞cos(2πf0t)g(t)e−j2πftdt=∫−∞∞12[ej2πf0t+e−j2πf0t]g(t)e−j2πftdt
Now ∫−∞∞12[ej2πf0t+e−j2πf0t]g(t)e−j2πftdt=12∫−∞∞e−j2π(f−f0)tg(t)dt+12∫−∞∞e−j2π(f+f0)tg(t)dt=12G(f−f0)+12G(f+f0)
So ℱ[cos(w0t)g(t)]=12[G(f−f0)+G(f+f0)]