Electronics 1

Amplifiers

Integrator

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The circuit at right integrates the input voltage $V_{in}$.

$V_{out}={\frac {-1}{R_{1}*C}}\int V_{in}dt$

"$R_{2}$ ; Provides negative feedback for low output impedance needs. But it also distorts the output."¹

Contributers

--Benjamin.henry 23:15, 10 January 2010 (UTC)

Sources

¹ Quick Study "Electronics 1, Part 2"