10/09 - Fourier Transform

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⟨ej2πnt/T∣ej2πmt/T⟩ =∫−∞∞ej2πnt/Te−j2πmt/Tdt
=∫−∞∞ej2π(n−m)t/Tdt
=∫−T/2T/2ej2π(n−m)t/Tdt Assuming the function is perodic with the period T
=Tδm,n

Fourier Transform

Remember from 10/02 - Fourier Series

  • αm=1T∫−T/2T/2x(t)e−j2πmt/Tdt
  • x(t)=x(t+T)=∑n=−∞∞αmej2πm/T

If we let T→∞

1T →df
nT →f Remember f=2πnT
T →∞
∑n=−∞∞1T →∫−∞∞()df

Definitions

F[x(t)] =X(f) =∫−∞∞x(t)e−j2πftdt =⟨x(t)∣ej2πft⟩
F−1[x(t)] =x(t) =∫−∞∞X(f)ej2πftdt =⟨X(f)∣e−j2πft⟩

Examples