Example problems of magnetic circuits

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Given:

A copper core with susceptibility χm=9.7×106

length of core L = 1 m

Gap length g = .01 m

cross sectional area A = .1 m

current I = 10A

N = 5 turns


Find: B

Solution: First we need to find the permeability of copper μ given by the equation
μ=μ0(1+χm)

Which yeilds μ=4×π×107(1+9.7×106)=1.2566×106

Now with this, the length and cross sectional area of the core we can solve for reluctance Rc by:

Rc=LμA=11.2566×106×.1=7.96×106

Similarly to get the reluctance of the gap

Failed to parse (unknown function "\time"): {\displaystyle  R_g = \frac {g}{\mu_0 (\sqrt{A} + g)^2} = \frac {.01}{4 \times \pi \times 10^{-7} (\sqrt{.1} + .01)^2} = 74.8 \time 10^{3}  }