Laplace Transform

$F(s)={\mathcal {L}}\left\{1\right\}=\int _{0}^{\infty }e^{-st}\,dt=$ ${\frac {1}{s}}$

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$F(s)={\mathcal {L}}\left\{t^{2}\right\}=\int _{0}^{\infty }e^{-st}\,dt=$ ${\frac {1}{s}}$