Fourier Example

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Revision as of 00:41, 19 January 2010 by Jorge.cruz (talk | contribs)
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Find the Fourier Series of the function:


f(x)={0,π<x<0π,0<x<π
bn=12π0ππsin(nx)dx,=1n(1cos(xπ))=1n(1(1)n)


We obtain b_2n = 0 and


b2n+1=22n+1

Therefore, the Fourier series of f(x) is

f(x)=π2+2(sin(x)+sin(3x)3+sin(5x)5+...)