ASN13 - Derive DFT relations: Difference between revisions

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Created page with ' Return to Homepage == Problem Statement == Is our method the same as Mark Flower's? See Wiki. Same # multiply and adds? See Notes 11/3/10. == Response == …'
 
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== Problem Statement ==
== Problem Statement ==


Is our method the same as Mark Flower's? See Wiki. Same # multiply and adds? See Notes 11/3/10.


Derive the following realtions:
a)      <math>DFT(x(k-l))\!</math>
b)      <math> DFT(e^{j2 \pi lk/N}x(k)\!</math>
c)      <math>\sum\limits_{k=0}^{N-1} x(k)y(k)^{*}=c\sum\limits_{k=0}^{N-1} X(n)Y(n)^{*}</math>


== Response ==
== Response ==




Mark
In progress

Latest revision as of 23:06, 30 November 2010

Return to Homepage


Problem Statement

Derive the following realtions:

a) DFT(x(kl))

b) DFT(ej2πlk/Nx(k)

c) k=0N1x(k)y(k)*=ck=0N1X(n)Y(n)*

Response

In progress