ASN13 - Derive DFT relations: Difference between revisions

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Derive the following realtions:
Derive the following realtions:
a)      <math>DFT(x(k-l))\!</math>
a)      <math>DFT(x(k-l))\!</math>
b)      <math> DFT(e^{j2 \pi lk/N}x(k)\!</math>
b)      <math> DFT(e^{j2 \pi lk/N}x(k)\!</math>
c)      <math>\sum\limits_{k=0}^{N-1} x(k)y(k)^{*}=c\sum\limits_{k=0}^{N-1} X(n)Y(n)^{*}</math>
c)      <math>\sum\limits_{k=0}^{N-1} x(k)y(k)^{*}=c\sum\limits_{k=0}^{N-1} X(n)Y(n)^{*}</math>


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Mark
In progress

Latest revision as of 23:06, 30 November 2010

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Problem Statement

Derive the following realtions:

a) DFT(x(kl))

b) DFT(ej2πlk/Nx(k)

c) k=0N1x(k)y(k)*=ck=0N1X(n)Y(n)*

Response

In progress