ASN10 - Quadrature sampling demonstration: Difference between revisions

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[[Jodi Hodge|Back to my home page]]
[[Jodi Hodge|Back to my home page]]


Assignment was actually done by professor in class.
Assignment was actually done in class by professor.

[http://www.example.com link title]
<br><b>Problem Statement</b><br><br>
Plot <math> \ \frac{2}{T} \sum_{n=1}^\infty sin\bigg(\frac{2 \pi nt}{T}\bigg) \!</math><br><br>
<b>Solution</b><br>

While we can't sum to infinity in the computer, we can get a close approximation summing over a large enough range of <math> n \!</math><br>

I found summing over <math> n = 1:1000 \!</math> was about the most the computer could handle reasonably.<br>

The following script was written in MATLAB to produce the desired plot. <br>
<pre>
clear all;
close all;
sum = 0;
T = 1;
t = -T:0.0001:T;
N = 1000;
for n = 1:N;
if n==0
h = 0;
else
h = 2/T;
end
sum = sum+h*sin(2*pi*n*t/T);
end
plot(t,sum)
title('Quadrature Sampling Waveform')
xlabel('time(T)')
ylabel('Sampling Waveform')
</pre><br>
Running the MATLAB script above gives us the following plot.<br>

[[Image:Quadrature sampling.jpg]]<br>

Revision as of 11:10, 3 December 2009

Back to my home page

Assignment was actually done in class by professor.

link title
Problem Statement

Plot

Solution

While we can't sum to infinity in the computer, we can get a close approximation summing over a large enough range of

I found summing over was about the most the computer could handle reasonably.

The following script was written in MATLAB to produce the desired plot.

clear all;
close all;
sum = 0;
T = 1;
t = -T:0.0001:T;
N = 1000;
for n = 1:N;
     if n==0
          h = 0;
     else
          h = 2/T;
     end
     sum = sum+h*sin(2*pi*n*t/T);
end
plot(t,sum)
title('Quadrature Sampling Waveform')
xlabel('time(T)')
ylabel('Sampling Waveform')


Running the MATLAB script above gives us the following plot.

Quadrature sampling.jpg