ASN6 a,b- fixing: Difference between revisions

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a)<math>S(0)= S(f)|_{f=0} = \int_{-\infty}^{\infty} s(t)e^{- j 2 \pi f t} dt = \int_{-\infty}^{\infty} s(t) dt</math>
a)<math>S(0)= S(f)|_{f=0} = \int_{-\infty}^{\infty} s(t)e^{- j 2 \pi f t} dt = \int_{-\infty}^{\infty} s(t) dt</math>


Remember dummy variable <math> \lambda= t-t_0 </math> Then <math> s(\lambda)= s(t-t_0)</math>
Remember dummy variable <math> \lambda= t-t_0 \! </math> Then <math> s(\lambda)= s(t-t_0) \! </math> and <math> \int_{- \infty}^{t} s(\lambda) \,d\lambda = \int_{- \infty}^{t} G (f)- G(f_0) \! </math>

Revision as of 18:40, 18 December 2009

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Problem Statement

6(a) Show . HINT:

6(b) If can you find in terms of ?

Answer a)

Remember dummy variable Then and