ASN3 - Class Notes October 5: Difference between revisions

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<math> n/T        \longrightarrow f </math>  
<math> n/T        \longrightarrow f </math>  
                
                
<math> \sum_{n=-\infty}^\infty  \frac{1}{T}\longrightarrow  \int_{-\infty] ^ \infty }(  )df \! </math>
<math> \sum_{n=-\infty}^\infty  \frac{1}{T}\longrightarrow  \int_{-\infty} ^ {\infty }(  )df \! </math>




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becomes as the limit is taken n/t becomes f
becomes as the limit is taken n/t becomes f
<math> x(t)=  \int_{-\infty ^ \infty} x(t')e^{ j2 \pi ft'} dt' e^{\frac{ j2 \pi ft}df \!</math>
<math> x(t)=  \int_{-\infty} ^ {\infty} x(t')e^{ j2 \pi ft'} dt' e^{\frac{ j2 \pi ft}df \!</math>





Revision as of 13:41, 3 December 2009

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1/T⟶df

n/T⟶f

∑n=−∞∞1T⟶∫−∞∞()df


Can we make an unperiodic signal and make it periodic by taking the limit?

x(t)=limT→∞1T(∫−T2T2x(t′)ej2πnt′Tdt′)ej2πntT

note that X(F)=ℱ[x(t)]∫−T2T2x(t′)ej2πnt′Tdt′

becomes as the limit is taken n/t becomes f Failed to parse (syntax error): {\displaystyle x(t)= \int_{-\infty} ^ {\infty} x(t')e^{ j2 \pi ft'} dt' e^{\frac{ j2 \pi ft}df \!}


THE GAME

LTI (Linear Time Invariant System)

Input LTI Output Reason



x2(t) . e−j2πmtT=∫−T2T2∑n=0∞anej2πntTe−j2πmtTdt=∑n=0∞an∫−T2T2ej2π(n−m)tTdt=∑n=0∞anTδmn