ASN3 - Class Notes October 5: Difference between revisions

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Can we make an unperiodic signal and make it periodic by taking the limit?
Can we make an unperiodic signal and make it periodic by taking the limit?


<math> x(t)= \lim_{T\to \infty} \frac {1}{T} (\int_{-\frac{T}{2}}^{\frac{T}{2}} x(t')e^{\frac{ j2 \pi nt'}{T}} dt' )e^{\frac{ j2 \pi nt}{T}} \!</math>
<math> x(t)= \lim_{T\to \infty} \frac {1}{T} (\int_{-\frac{T}{2}}^{\frac{T}{2}} x(t')e^{\frac{ -j2 \pi nt'}{T}} dt' )e^{\frac{ j2 \pi nt}{T}} \!</math>


note that  
note that  
<math> X(F)= \mathcal{F}[x(t)] \int_{-\frac{T}{2}}^{\frac{T}{2}} x(t')e^{\frac{ j2 \pi nt'}{T}} dt' \!</math>
<math> X(F)= \mathcal{F}[x(t)] \int_{-\frac{T}{2}}^{\frac{T}{2}} x(t')e^{\frac{ -j2 \pi nt'}{T}} dt' \!</math>


becomes as the limit is taken n/t becomes f
becomes as the limit is taken n/t becomes f
<math> x(t)=  \int_{-\infty} ^ {\infty} (\int_{-\infty} ^ {\infty} x(t')e^{ j2 \pi ft'} dt') e^{ j2 \pi ft}df \!</math>
<math> x(t)=  \int_{-\infty} ^ {\infty} [\int_{-\infty} ^ {\infty} x(t')e^{ -j2 \pi ft'} dt'] e^{ j2 \pi ft}df \!</math>
 


<math> x(t)=  \int_{-\infty} ^ {\infty} x(t')[\int_{-\infty} ^ {\infty} e^{ j2 \pi f(t'-t)} df ]dt'  \!</math>


THE GAME  
THE GAME  

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1/T⟶df

n/T⟶f

∑n=−∞∞1T⟶∫−∞∞()df


Can we make an unperiodic signal and make it periodic by taking the limit?

x(t)=limT→∞1T(∫−T2T2x(t′)e−j2πnt′Tdt′)ej2πntT

note that X(F)=ℱ[x(t)]∫−T2T2x(t′)e−j2πnt′Tdt′

becomes as the limit is taken n/t becomes f x(t)=∫−∞∞[∫−∞∞x(t′)e−j2πft′dt′]ej2πftdf

x(t)=∫−∞∞x(t′)[∫−∞∞ej2πf(t′−t)df]dt′

THE GAME

LTI (Linear Time Invariant System)

Input LTI Output Reason



x2(t) . e−j2πmtT=∫−T2T2∑n=0∞anej2πntTe−j2πmtTdt=∑n=0∞an∫−T2T2ej2π(n−m)tTdt=∑n=0∞anTδmn