ASN3 - Class Notes October 5: Difference between revisions

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<math> x(t)=  \int_{-\infty} ^ {\infty} x(t')\delta_(t'-t) dt'  \!</math>
<math> x(t)=  \int_{-\infty} ^ {\infty} x(t')\delta_(t'-t) dt'  \!</math>


                THE GAME  
<math>                      THE GAME </math>


LTI (Linear Time Invariant System)
<math>              LTI (Linear Time Invariant System) </math>


Input    LTI                       Output         Reason
<math> Input    LTI                             Output                                 Reason</math>


<math> x(t)\longrightarrow  \int_{-\infty} ^ {\infty} x(t')\delta_(t'-t) dt'  \!</math>
<math> x(t)\longrightarrow  \int_{-\infty} ^ {\infty} x(t')\delta_(t'-t) dt'  \!</math> Superposition
<math> X(f)\longrightarrow  \int_{-\infty} ^ {\infty} X(f')\delta_(f'-f) df'  \!</math>
<math> X(f)\longrightarrow  \int_{-\infty} ^ {\infty} X(f')\delta_(f'-f) df'  \!</math>     "

Revision as of 13:58, 3 December 2009

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1/Tdf

n/Tf

n=1T()df


Can we make an unperiodic signal and make it periodic by taking the limit?

x(t)=limT1T(T2T2x(t)ej2πntTdt)ej2πntT

note that X(F)=[x(t)]T2T2x(t)ej2πntTdt

becomes as the limit is taken n/t becomes f x(t)=[x(t)ej2πftdt]ej2πftdf

x(t)=x(t)[ej2πf(tt)df]dt

note that the defination of the delta function is ej2πf(tt)df

x(t)=x(t)δ(tt)dt

THEGAME

LTI(LinearTimeInvariantSystem)

InputLTIOutputReason

x(t)x(t)δ(tt)dt Superposition X(f)X(f)δ(ff)df "