ASN6 a,b- fixing: Difference between revisions

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'''Answer'''
'''Answer'''
a)<math>s(0)= S(f)|_{f=0} = \int_{-\infty}^{\infty} s(t)e^{- j 2 \pi f t} dt = \int_{-\infty}^{\infty} s(t) dt</math>
a)<math>S(0)= S(f)|_{f=0} = \int_{-\infty}^{\infty} s(t)e^{- j 2 \pi f t} dt = \int_{-\infty}^{\infty} s(t) dt</math>
 
Remember dummy variable <math> \lambda= t-t_0 </math> Then <math> s(\lambda)= s(t-t_0)</math>

Revision as of 19:31, 18 December 2009

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Problem Statement

6(a) Show ℱ[∫−∞ts(λ)dλ]=S(f)j2πf if S(0)=0. HINT: S(0)=S(f)|f=0=∫−∞∞s(t)e−j2π(f→0)tdt=∫−∞∞s(t)dt

6(b) If S(0)≠0 can you find ℱ[∫−∞ts(λ)dλ] in terms of S(0)?

Answer a)S(0)=S(f)|f=0=∫−∞∞s(t)e−j2πftdt=∫−∞∞s(t)dt

Remember dummy variable λ=t−t0 Then s(λ)=s(t−t0)