ASN10 - Quadrature sampling demonstration: Difference between revisions

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[[Jodi Hodge|Back to my home page]]
[[Jodi Hodge|Back to my home page]]


Assignment was actually done by professor in class.
Assignment was actually done in class by professor.
 
[http://www.example.com link title]
<br><b>Problem Statement</b><br><br>
Plot <math> \ \frac{2}{T} \sum_{n=1}^\infty sin\bigg(\frac{2 \pi nt}{T}\bigg) \!</math><br><br>
<b>Solution</b><br>
 
While we can't sum to infinity in the computer, we can get a close approximation summing over a large enough range of <math> n  \!</math><br>
 
I found summing over <math> n = 1:1000 \!</math> was about the most the computer could handle reasonably.<br>
 
The following script was written in MATLAB to produce the desired plot. <br>
<pre>
clear all;
close all;
sum = 0;
T = 1;
t = -T:0.0001:T;
N = 1000;
for n = 1:N;
    if n==0
          h = 0;
    else
          h = 2/T;
    end
    sum = sum+h*sin(2*pi*n*t/T);
end
plot(t,sum)
title('Quadrature Sampling Waveform')
xlabel('time(T)')
ylabel('Sampling Waveform')
</pre><br>
Running the MATLAB script above gives us the following plot.<br>
 
[[Image:Quadrature sampling.jpg]]<br>

Revision as of 12:10, 3 December 2009

Back to my home page

Assignment was actually done in class by professor.

link title
Problem Statement

Plot 2Tn=1sin(2πntT)

Solution

While we can't sum to infinity in the computer, we can get a close approximation summing over a large enough range of n

I found summing over n=1:1000 was about the most the computer could handle reasonably.

The following script was written in MATLAB to produce the desired plot.

clear all;
close all;
sum = 0;
T = 1;
t = -T:0.0001:T;
N = 1000;
for n = 1:N;
     if n==0
          h = 0;
     else
          h = 2/T;
     end
     sum = sum+h*sin(2*pi*n*t/T);
end
plot(t,sum)
title('Quadrature Sampling Waveform')
xlabel('time(T)')
ylabel('Sampling Waveform')


Running the MATLAB script above gives us the following plot.