ASN3 - Class Notes October 5

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$1/T\longrightarrow df$

$n/T\longrightarrow f$

$\sum _{n=-\infty }^{\infty }{\frac {1}{T}}\longrightarrow \int _{-\infty ]^{\infty }}()df\!$

Can we make an unperiodic signal and make it periodic by taking the limit?

Failed to parse (syntax error): {\displaystyle x(t)= \lim_{T\to \infty \frac {1}{T} (\int_{-\frac{T}{2}}^{\frac{T}{2}} x(t')e^{\frac{ j2 \pi nt'}{T}} dt' )e^{\frac{ j2 \pi nt}{T}} \!}

note that f replaced with n/t and that $X(F)={\mathcal {F}}[x(t)]\int _{-{\frac {T}{2}}}^{\frac {T}{2}}x(t')e^{\frac {j2\pi nt'}{T}}dt'\!$

$X(F)={\mathcal {F}}[x(t)]\!<math>'''THEGAME'''LTI(LinearTimeInvariantSystem)InputLTIOutputReason<math>x2(t)\!$ . $e^{\frac {-j2\pi mt}{T}}=\int _{-{\frac {T}{2}}}^{\frac {T}{2}}\sum _{n=0}^{\infty }a_{n}e^{\frac {j2\pi nt}{T}}e^{\frac {-j2\pi mt}{T}}dt=\sum _{n=0}^{\infty }a_{n}\int _{-{\frac {T}{2}}}^{\frac {T}{2}}e^{\frac {j2\pi (n-m)t}{T}}dt=\sum _{n=0}^{\infty }a_{n}T\delta _{mn}\!$