ASN3 - Class Notes October 5: Difference between revisions

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Can we make an unperiodic signal and make it periodic by taking the limit?
Can we make an unperiodic signal and make it periodic by taking the limit?


<math> x(t)= \lim_{T\to \infty} \frac {1}{T} (\int_{-\frac{T}{2}}^{\frac{T}{2}} x(t')e^{\frac{ j2 \pi nt'}{T}} dt' )e^{\frac{ j2 \pi nt}{T}} \!</math>
<math> x(t)= \lim_{T\to \infty} \frac {1}{T} (\int_{-\frac{T}{2}}^{\frac{T}{2}} x(t')e^{\frac{ -j2 \pi nt'}{T}} dt' )e^{\frac{ j2 \pi nt}{T}} \!</math>


note that  
note that  
<math> X(F)= \mathcal{F}[x(t)] \int_{-\frac{T}{2}}^{\frac{T}{2}} x(t')e^{\frac{ j2 \pi nt'}{T}} dt' \!</math>
<math> X(F)= \mathcal{F}[x(t)] \int_{-\frac{T}{2}}^{\frac{T}{2}} x(t')e^{\frac{ -j2 \pi nt'}{T}} dt' \!</math>


becomes as the limit is taken n/t becomes f
becomes as the limit is taken n/t becomes f
<math> x(t)=  \int_{-\infty} ^ {\infty} (\int_{-\infty} ^ {\infty} x(t')e^{ j2 \pi ft'} dt') e^{ j2 \pi ft}df \!</math>
<math> x(t)=  \int_{-\infty} ^ {\infty} [\int_{-\infty} ^ {\infty} x(t')e^{ -j2 \pi ft'} dt'] e^{ j2 \pi ft}df \!</math>
 


<math> x(t)=  \int_{-\infty} ^ {\infty} x(t')[\int_{-\infty} ^ {\infty} e^{ j2 \pi f(t'-t)} df ]dt'  \!</math>


THE GAME  
THE GAME  

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1/Tdf

n/Tf

n=1T()df


Can we make an unperiodic signal and make it periodic by taking the limit?

x(t)=limT1T(T2T2x(t)ej2πntTdt)ej2πntT

note that X(F)=[x(t)]T2T2x(t)ej2πntTdt

becomes as the limit is taken n/t becomes f x(t)=[x(t)ej2πftdt]ej2πftdf

x(t)=x(t)[ej2πf(tt)df]dt

THE GAME

LTI (Linear Time Invariant System)

Input LTI Output Reason



x2(t) . ej2πmtT=T2T2n=0anej2πntTej2πmtTdt=n=0anT2T2ej2π(nm)tTdt=n=0anTδmn