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a)Remember that dummy variable <math> \lambda \!</math>  was used in substitution such that <math> \lambda= t-t_0 \! </math>  
a)Remember that dummy variable <math> \lambda \!</math>  was used in substitution such that <math> \lambda= t-t_0 \! </math>  


This means <math> s(\lambda)= s(t-t_0)= \mathcal{F}\left[ S (f)- S(f_0) \right] \!</math>  
Then <math> s(\lambda)= s(t-t_0)= \mathcal{F}\left[ S (f)- S(f_0) \right] \!</math>  


In the problemstatement it says to make <math>S(f_0)=0 \!</math>
and <math> \int_{- \infty}^{t} s(\lambda) \,d\lambda = \int_{- \infty}^{t}\mathcal{F}\left[ S (f)- S(f_0) \right] \,d\lambda \! </math>
 
 
 
 
</math> and <math> \int_{- \infty}^{t} s(\lambda) \,d\lambda = \int_{- \infty}^{t}\mathcal{F}\left[ S (f)- S(f_0) \right] \,d\lambda \! </math>




The problem statement says to make <math>S(f_0)=0 \!</math> that makes the above equation simplify to


<math> \int_{- \infty}^{t} s(\lambda) \,d\lambda = \int_{- \infty}^{t}\mathcal{F}\left[ S (f) \right] \,dt \! </math>
<math> \int_{- \infty}^{t} s(\lambda) \,d\lambda = \int_{- \infty}^{t}\mathcal{F}\left[ S (f) \right] \,dt \! </math>

Revision as of 21:40, 18 December 2009

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Problem Statement

6(a) Show [ts(λ)dλ]=S(f)j2πf if S(0)=0.

6(b) If S(0)0 can you find [ts(λ)dλ] in terms of S(0)?

Answer

a)Remember that dummy variable λ was used in substitution such that λ=tt0

Then s(λ)=s(tt0)=[S(f)S(f0)]

and ts(λ)dλ=t[S(f)S(f0)]dλ


The problem statement says to make S(f0)=0 that makes the above equation simplify to

ts(λ)dλ=t[S(f)]dt

1[S(f)S(f0)]=tej2πftdtS(f)df=ej2πftj2πfS(f)df=

ts(λ)dλ=S(f)ej2πftj2πfdf=1[S(f)j2πf]

Therefore [ts(λ)dλ]=S(f)j2πf




In my notations Failed to parse (syntax error): {\displaystyle S(f_0)=S(f)|_{f=0 \!}

The problem statement says let f0=0 where S(0)=S(f)|f=0=s(t)ej2πftdt=s(t)dt

 if S(0)=0s(t)dt=0