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Problem Statement
6(a) Show F [ ∫ − ∞ t s ( λ ) d λ ] = S ( f ) j 2 π f if S ( 0 ) = 0 {\displaystyle {\mathcal {F}}\left[\int _{-\infty }^{t}s(\lambda )\,d\lambda \right]={\frac {S(f)}{j2\pi f}}{\mbox{ if }}S(0)=0} . Hint: S ( 0 ) = S ( f ) | f = 0 = ∫ − ∞ ∞ s ( t ) e − j 2 π ( f → 0 ) t d t = ∫ − ∞ ∞ s ( t ) d t {\displaystyle S(0)=S(f)\vert _{_{f=0}}=\int _{-\infty }^{\infty }s(t)e^{-j2\pi (f\rightarrow 0)t}\,dt=\int _{-\infty }^{\infty }s(t)\,dt}
6(b) If S ( 0 ) ≠ 0 {\displaystyle S(0)\neq 0} can you find F [ ∫ − ∞ t s ( λ ) d λ ] {\displaystyle {\mathcal {F}}\left[\int _{-\infty }^{t}s(\lambda )\,d\lambda \right]} in terms of S ( 0 ) {\displaystyle \displaystyle S(0)} ?
Answer
a)
Remember dummy variable λ = t − t 0 {\displaystyle \lambda =t-t_{0}\!} Then s ( λ ) = s ( t − t 0 ) = F [ S ( f ) − S ( f 0 ) ] {\displaystyle s(\lambda )=s(t-t_{0})={\mathcal {F}}\left[S(f)-S(f_{0})\right]\!} and ∫ − ∞ t s ( λ ) d λ = ∫ − ∞ t F [ S ( f ) − S ( f 0 ) ] d λ {\displaystyle \int _{-\infty }^{t}s(\lambda )\,d\lambda =\int _{-\infty }^{t}{\mathcal {F}}\left[S(f)-S(f_{0})\right]\,d\lambda \!}
f 0 = 0 {\displaystyle f_{0}=0\!} where S ( 0 ) = S ( f ) | f = 0 = ∫ − ∞ ∞ s ( t ) e − j 2 π f t d t = ∫ − ∞ ∞ s ( t ) d t {\displaystyle S(0)=S(f)|_{f=0}=\int _{-\infty }^{\infty }s(t)e^{-j2\pi ft}dt=\int _{-\infty }^{\infty }s(t)dt\!}
if S ( 0 ) = 0 ∫ − ∞ ∞ s ( t ) d t = 0 {\displaystyle {\mbox{ if }}S(0)=0\,\,\,\int _{-\infty }^{\infty }s(t)dt=0\!}
∫ − ∞ t s ( λ ) d λ = ∫ − ∞ t F [ S ( f ) ] d λ {\displaystyle \int _{-\infty }^{t}s(\lambda )\,d\lambda =\int _{-\infty }^{t}{\mathcal {F}}\left[S(f)\right]\,d\lambda \!}
F [ S ( f ) − S ( f 0 ) ] = ∫ − ∞ t e − j 2 π f t ∫ − ∞ ∞ S ( f ) e − j 2 π f t d f = e − j 2 π f t − j 2 π f ∫ − ∞ ∞ S ( f ) d f {\displaystyle {\mathcal {F}}\left[S(f)-S(f_{0})\right]=\int _{-\infty }^{t}e^{-j2\pi ft}\int _{-\infty }^{\infty }S(f)e^{-j2\pi ft}\,df={\frac {e^{-j2\pi ft}}{-j2\pi f}}\int _{-\infty }^{\infty }S(f)\,df}
![{\displaystyle {\mathcal {F}}\left[\int _{-\infty }^{t}s(\lambda )\,d\lambda \right]={\frac {S(f)}{j2\pi f}}{\mbox{ if }}S(0)=0}](https://wikimedia.org/api/rest_v1/media/math/render/svg/3e30ea2d81a3c0586359e282685bc252899dbaab)
. Hint: 
can you find ![{\displaystyle {\mathcal {F}}\left[\int _{-\infty }^{t}s(\lambda )\,d\lambda \right]}](https://wikimedia.org/api/rest_v1/media/math/render/svg/0af3b7173a594a013131920839a34842568e41f3)
in terms of 
?
Then ![{\displaystyle s(\lambda )=s(t-t_{0})={\mathcal {F}}\left[S(f)-S(f_{0})\right]\!}](https://wikimedia.org/api/rest_v1/media/math/render/svg/0a698d9b80c3ed2d1235e2c81c6f71635c9e722d)
and ![{\displaystyle \int _{-\infty }^{t}s(\lambda )\,d\lambda =\int _{-\infty }^{t}{\mathcal {F}}\left[S(f)-S(f_{0})\right]\,d\lambda \!}](https://wikimedia.org/api/rest_v1/media/math/render/svg/426689bcd3afea3043dbafdd065ae7f95a1a90cd)
where 
![{\displaystyle \int _{-\infty }^{t}s(\lambda )\,d\lambda =\int _{-\infty }^{t}{\mathcal {F}}\left[S(f)\right]\,d\lambda \!}](https://wikimedia.org/api/rest_v1/media/math/render/svg/b95fb296bf5b12d9ae33250f8511cf773c0056e0)
![{\displaystyle {\mathcal {F}}\left[S(f)-S(f_{0})\right]=\int _{-\infty }^{t}e^{-j2\pi ft}\int _{-\infty }^{\infty }S(f)e^{-j2\pi ft}\,df={\frac {e^{-j2\pi ft}}{-j2\pi f}}\int _{-\infty }^{\infty }S(f)\,df}](https://wikimedia.org/api/rest_v1/media/math/render/svg/09a86df7102e267aafcf87ff81e8816b5ffe88f0)