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Problem Statement
6(a) Show F [ ∫ − ∞ t s ( λ ) d λ ] = S ( f ) j 2 π f if S ( 0 ) = 0 {\displaystyle {\mathcal {F}}\left[\int _{-\infty }^{t}s(\lambda )\,d\lambda \right]={\frac {S(f)}{j2\pi f}}{\mbox{ if }}S(0)=0} .
6(b) If S ( 0 ) ≠ 0 {\displaystyle S(0)\neq 0} can you find F [ ∫ − ∞ t s ( λ ) d λ ] {\displaystyle {\mathcal {F}}\left[\int _{-\infty }^{t}s(\lambda )\,d\lambda \right]} in terms of S ( 0 ) {\displaystyle \displaystyle S(0)} ?
Answer
a)
Remember that dummy variable λ {\displaystyle \lambda } was used as a substitution such that λ = t − t 0 {\displaystyle \lambda =t-t_{0}\!}
See then that s ( λ ) = s ( t − t 0 ) = F [ S ( f ) − S ( f 0 ) ] < m a t h > f 0 = 0 {\displaystyle s(\lambda )=s(t-t_{0})={\mathcal {F}}\left[S(f)-S(f_{0})\right]\!<math>f_{0}=0\!} where S ( 0 ) = S ( f ) | f = 0 = ∫ − ∞ ∞ s ( t ) e − j 2 π f t d t = ∫ − ∞ ∞ s ( t ) d t {\displaystyle S(0)=S(f)|_{f=0}=\int _{-\infty }^{\infty }s(t)e^{-j2\pi ft}dt=\int _{-\infty }^{\infty }s(t)dt\!}
if S ( 0 ) = 0 ∫ − ∞ ∞ s ( t ) d t = 0 {\displaystyle {\mbox{ if }}S(0)=0\,\,\,\int _{-\infty }^{\infty }s(t)dt=0\!}
</math> and ∫ − ∞ t s ( λ ) d λ = ∫ − ∞ t F [ S ( f ) − S ( f 0 ) ] d λ {\displaystyle \int _{-\infty }^{t}s(\lambda )\,d\lambda =\int _{-\infty }^{t}{\mathcal {F}}\left[S(f)-S(f_{0})\right]\,d\lambda \!}
∫ − ∞ t s ( λ ) d λ = ∫ − ∞ t F [ S ( f ) ] d t {\displaystyle \int _{-\infty }^{t}s(\lambda )\,d\lambda =\int _{-\infty }^{t}{\mathcal {F}}\left[S(f)\right]\,dt\!}
F − 1 [ S ( f ) − S ( f 0 ) ] = ∫ − ∞ t e j 2 π f t d t ∫ − ∞ ∞ S ( f ) d f = e j 2 π f t j 2 π f ∫ − ∞ ∞ S ( f ) d f = {\displaystyle {\mathcal {F}}^{-1}\left[S(f)-S(f_{0})\right]=\int _{-\infty }^{t}e^{j2\pi ft}\,dt\int _{-\infty }^{\infty }S(f)\,df={\frac {e^{j2\pi ft}}{j2\pi f}}\int _{-\infty }^{\infty }S(f)\,df=\!}
∫ − ∞ t s ( λ ) d λ = ∫ ∞ ∞ S ( f ) e j 2 π f t j 2 π f d f = F − 1 [ S ( f ) j 2 π f ] {\displaystyle \int _{-\infty }^{t}s(\lambda )\,d\lambda =\int _{\infty }^{\infty }S(f){\frac {e^{j2\pi ft}}{j2\pi f}}\,df={\mathcal {F}}^{-1}\left[{\frac {S(f)}{j2\pi f}}\right]\!}
Therefore F [ ∫ − ∞ t s ( λ ) d λ ] = S ( f ) j 2 π f {\displaystyle {\mathcal {F}}\left[\int _{-\infty }^{t}s(\lambda )\,d\lambda \right]={\frac {S(f)}{j2\pi f}}\!}
![{\displaystyle {\mathcal {F}}\left[\int _{-\infty }^{t}s(\lambda )\,d\lambda \right]={\frac {S(f)}{j2\pi f}}{\mbox{ if }}S(0)=0}](https://wikimedia.org/api/rest_v1/media/math/render/svg/3e30ea2d81a3c0586359e282685bc252899dbaab)
.
can you find ![{\displaystyle {\mathcal {F}}\left[\int _{-\infty }^{t}s(\lambda )\,d\lambda \right]}](https://wikimedia.org/api/rest_v1/media/math/render/svg/0af3b7173a594a013131920839a34842568e41f3)
in terms of 
?
was used as a substitution such that 
![{\displaystyle s(\lambda )=s(t-t_{0})={\mathcal {F}}\left[S(f)-S(f_{0})\right]\!<math>f_{0}=0\!}](https://wikimedia.org/api/rest_v1/media/math/render/svg/745d9c07f36645f62707ef98b44ffa0e4f2e1d88)
where 
![{\displaystyle \int _{-\infty }^{t}s(\lambda )\,d\lambda =\int _{-\infty }^{t}{\mathcal {F}}\left[S(f)-S(f_{0})\right]\,d\lambda \!}](https://wikimedia.org/api/rest_v1/media/math/render/svg/426689bcd3afea3043dbafdd065ae7f95a1a90cd)
![{\displaystyle \int _{-\infty }^{t}s(\lambda )\,d\lambda =\int _{-\infty }^{t}{\mathcal {F}}\left[S(f)\right]\,dt\!}](https://wikimedia.org/api/rest_v1/media/math/render/svg/d31315811e9778e11a05fa2750ba76d55b513dd0)
![{\displaystyle {\mathcal {F}}^{-1}\left[S(f)-S(f_{0})\right]=\int _{-\infty }^{t}e^{j2\pi ft}\,dt\int _{-\infty }^{\infty }S(f)\,df={\frac {e^{j2\pi ft}}{j2\pi f}}\int _{-\infty }^{\infty }S(f)\,df=\!}](https://wikimedia.org/api/rest_v1/media/math/render/svg/55fdd4a6f52030cfc52d13a92f09e7048590db6f)
![{\displaystyle \int _{-\infty }^{t}s(\lambda )\,d\lambda =\int _{\infty }^{\infty }S(f){\frac {e^{j2\pi ft}}{j2\pi f}}\,df={\mathcal {F}}^{-1}\left[{\frac {S(f)}{j2\pi f}}\right]\!}](https://wikimedia.org/api/rest_v1/media/math/render/svg/1a55ae349fb07fecbca1c1baf4c66ed8408702d6)
![{\displaystyle {\mathcal {F}}\left[\int _{-\infty }^{t}s(\lambda )\,d\lambda \right]={\frac {S(f)}{j2\pi f}}\!}](https://wikimedia.org/api/rest_v1/media/math/render/svg/27447ac8285d60d653060b8d93c9c08046a3069b)