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1 / T ⟶ d f {\displaystyle 1/T\longrightarrow df}
n / T ⟶ f {\displaystyle n/T\longrightarrow f}
∑ n = − ∞ ∞ 1 T ⟶ ∫ − ∞ ] ∞ ( ) d f {\displaystyle \sum _{n=-\infty }^{\infty }{\frac {1}{T}}\longrightarrow \int _{-\infty ]^{\infty }}()df\!}
Can we make an unperiodic signal and make it periodic by taking the limit?
x ( t ) = lim T → ∞ 1 T ( ∫ − T 2 T 2 x ( t ′ ) e j 2 π n t ′ T d t ′ ) e j 2 π n t T {\displaystyle x(t)=\lim _{T\to \infty }{\frac {1}{T}}(\int _{-{\frac {T}{2}}}^{\frac {T}{2}}x(t')e^{\frac {j2\pi nt'}{T}}dt')e^{\frac {j2\pi nt}{T}}\!}
note that f replaced with n/t and that X ( F ) = F [ x ( t ) ] ∫ − T 2 T 2 x ( t ′ ) e j 2 π n t ′ T d t ′ {\displaystyle X(F)={\mathcal {F}}[x(t)]\int _{-{\frac {T}{2}}}^{\frac {T}{2}}x(t')e^{\frac {j2\pi nt'}{T}}dt'\!}
X ( F ) = F [ x ( t ) ] < m a t h > ‴ T H E G A M E ‴ L T I ( L i n e a r T i m e I n v a r i a n t S y s t e m ) I n p u t L T I O u t p u t R e a s o n < m a t h > x 2 ( t ) {\displaystyle X(F)={\mathcal {F}}[x(t)]\!<math>'''THEGAME'''LTI(LinearTimeInvariantSystem)InputLTIOutputReason<math>x2(t)\!} . e − j 2 π m t T = ∫ − T 2 T 2 ∑ n = 0 ∞ a n e j 2 π n t T e − j 2 π m t T d t = ∑ n = 0 ∞ a n ∫ − T 2 T 2 e j 2 π ( n − m ) t T d t = ∑ n = 0 ∞ a n T δ m n {\displaystyle e^{\frac {-j2\pi mt}{T}}=\int _{-{\frac {T}{2}}}^{\frac {T}{2}}\sum _{n=0}^{\infty }a_{n}e^{\frac {j2\pi nt}{T}}e^{\frac {-j2\pi mt}{T}}dt=\sum _{n=0}^{\infty }a_{n}\int _{-{\frac {T}{2}}}^{\frac {T}{2}}e^{\frac {j2\pi (n-m)t}{T}}dt=\sum _{n=0}^{\infty }a_{n}T\delta _{mn}\!}