ASN6 a,b- fixing

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Problem Statement

6(a) Show [ts(λ)dλ]=S(f)j2πf if S(0)=0. Hint: S(0)=S(f)|f=0=s(t)ej2π(f0)tdt=s(t)dt

6(b) If S(0)0 can you find [ts(λ)dλ] in terms of S(0)?

Answer

a)

Remember dummy variable λ=tt0 Then s(λ)=s(tt0)=[S(f)S(f0)] and ts(λ)dλ=t[S(f)S(f0)]dλ

f0=0 where S(0)=S(f)|f=0=s(t)ej2πftdt=s(t)dt

 if S(0)=0s(t)dt=0


ts(λ)dλ=t[S(f)]dt

Failed to parse (syntax error): {\displaystyle \mathcal{F}\left[ S (f)- S(f_0) \right] = \int_{- \infty}^{t} e^{-j2 \pi f t} \,dt \int_{- \infty}^{\infty} S(f)\,df = \frac{ e^{-j2 \pi f t}} {-j2 \pi f }\int_{- \infty}^{\infty} S(f) \,df =\infty}^{\infty} S(f)\frac{ e^{-j2 \pi f t}} {-j2 \pi f }\,df }